A particle of mass m is projected with velocity u at an angle θ θ with horizontal. During the period when the particle descends from highest point to the position where its velocity vector makes an angle θ θ /2 with horizontal. Work done by the gravity force is
A
mu 2 tan 2 θ θ /2
B
mu 2 tan 2 θ θ
C
mu 2 cos 2 θ θ tan 2 θ θ /2
D
mu 2 cos 2 θ θ /2 sin 2 θ θ
Text Solution
Verified by ExpertsThe correct answer is:
C
As horizontal component of velocity does not change, v cos θ θ /2 = u cos θ θ , v = 
W gravity = Δ Δ k = 
mv 2 − − 
m(u cos θ θ ) 2 = 
mu 2 cos 2 θ θ tan 2 θ θ /2 Hence, the correct choice is
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